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Harlan Township, Fayette County, Iowa : ウィキペディア英語版 | Harlan Township, Fayette County, Iowa
Harlan Township is one of twenty townships in Fayette County, Iowa, USA. As of the 2010 census, its population was 871. ==Geography== According to the United States Census Bureau, Harlan Township covers an area of 36.79 square miles (95.28 square kilometers); of this, 36.76 square miles (95.22 square kilometers, 99.94 percent) is land and 0.03 square miles (0.07 square kilometers, 0.07 percent) is water.
抄文引用元・出典: フリー百科事典『 ウィキペディア(Wikipedia)』 ■ウィキペディアで「Harlan Township, Fayette County, Iowa」の詳細全文を読む
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